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Theorem efqd 250
Description: Deduction form of ax-efq 248 (Contributed by la korvo, 4-Jan-2025.)
Hypothesis
Ref Expression
efqd.0ganai broda gi naku brode
Assertion
Ref Expression
efqdganai broda gi ganai brode gi brodi

Proof of Theorem efqd
StepHypRef Expression
1 efqd.0 . 2ganai broda gi naku brode
2 ax-efq 248 . 2ganai naku brode gi ganai brode gi brodi
31, 2syl 20 1ganai broda gi ganai brode gi brodi
Colors of variables: sumti selbri bridi
Syntax hints:  ganai bgan 9  naku bnk 236
This theorem was proved from axioms:  ax-mp 10  ax-k 11  ax-s 15  ax-efq 248
This theorem is referenced by: (None)
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