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Theorem du-mintu 341
Description: Suggested by baseline definition of {mintu}: {du} is {mintu} without a standard of comparison, which is a stronger condition. (Contributed by la korvo, 25-Jun-2024.)
Hypothesis
Ref Expression
du-mintu.0ko'a du ko'e
Assertion
Ref Expression
du-mintuko'a mintu ko'e ko'i

Proof of Theorem du-mintu
Dummy variable bu'a is distinct from all other variables.
StepHypRef Expression
1 tsb 1 . . . 4 brirebla ckaji
21tss 2 . . 3 brirebla ckaji ko'i
3 du-mintu.0 . . . 4ko'a du ko'e
43dui 216 . . 3ro bu'a zo'u ko'a .o ko'e bu'a
52, 4ax-ro-inst-2u 207 . 2ko'a .o ko'e ckaji ko'i
65minturi 338 1ko'a mintu ko'e ko'i
Colors of variables: sumti selbri bridi
Syntax hints:  tsb 1  tss 2  .o sjo 166  ckaji sbckaji 305
This theorem was proved from axioms:  ax-mp 10  ax-k 11  ax-s 15  ax-ge-le 43  ax-ge-re 44  ax-ge-in 45  ax-ro-inst-2u 207
This theorem depends on definitions:  df-go 61  df-du 215  df-mintu 336
This theorem is referenced by: (None)
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