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Theorem du-syms 262
Description: Commute an equality in an antecedent. (Contributed by la korvo, 11-Aug-2026.)
Hypothesis
Ref Expression
du-syms.0ganai ko'a du ko'e gi broda
Assertion
Ref Expression
du-symsganai ko'e du ko'a gi broda

Proof of Theorem du-syms
StepHypRef Expression
1 du-sym-ganai 260 . 2ganai ko'e du ko'a gi ko'a du ko'e
2 du-syms.0 . 2ganai ko'a du ko'e gi broda
31, 2syl 21 1ganai ko'e du ko'a gi broda
Colors of variables: sumti selbri bridi
Syntax hints:   du sbdu 250
This theorem was proved from axioms:  ax-mp 10  ax-k 11  ax-s 15  ax-ge-le 48  ax-ge-re 49  ax-ge-in 50  ax-gen2 227  ax-qi2 239  ax-du-trans 258
This theorem depends on definitions:  df-go 83  df-o 198  df-du 251
This theorem is referenced by:  stdpc7  460
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